zzy
097dbdcc2a
- 实现了条件分支、无条件跳转和函数调用的机器码生成 - 添加了跳转目标地址回填机制，处理条件分支和跳转指令的偏移量 - 改进了寄存器分配逻辑，支持函数调用返回值的处理 - 重构了位置解析函数，从返回指针改为传入引用参数 fix(ast2ir): 移除无用的注释代码 - 删除了关于一元操作符映射的注释代码 test: 更新测试框架和测试用例 - 修改测试框架以支持新的可执行文件输出格式 - 添加了条件分支、循环和函数调用的测试用例 - 使用TOML配置文件管理期望的返回值 - 替换标准库头文件为自定义头文件以减少依赖
88 lines
2.7 KiB
C
88 lines
2.7 KiB
C
#include <scc_ast2ir.h>
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#include <scc_ir2mcode.h>
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#include <scc_lexer.h>
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#include <scc_parser.h>
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#include <sccf2pe.h>
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#include <stdio.h>
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void test_example(const char *input, cbool need_sema, const char *name) {
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int res = 0;
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scc_sstream_t mem_stream;
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res = scc_sstream_init_by_buffer(&mem_stream, input, scc_strlen(input),
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false, 16);
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Assert(res == 0);
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scc_lexer_t lexer;
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scc_lexer_init(&lexer, scc_sstream_to_ring(&mem_stream));
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scc_lexer_tok_ring_t *tok_ring = scc_lexer_to_ring(&lexer, 64, false);
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scc_parser_t parser;
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if (need_sema) {
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scc_sema_callbacks_t sema_callbacks;
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scc_sema_init(&sema_callbacks);
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scc_parser_init(&parser, tok_ring, &sema_callbacks);
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} else {
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scc_parser_init(&parser, tok_ring, null);
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}
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scc_ast_translation_unit_t *tu = scc_parse_translation_unit(&parser);
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scc_ast2ir_ctx_t ast2ir_ctx;
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#include <abi/win_x64_type_abi.h>
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scc_ast2ir_ctx_init(&ast2ir_ctx, scc_win_x64_type_abi);
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scc_ast2ir_translation_unit(&ast2ir_ctx, tu);
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scc_ir2mcode_ctx_t mcode_ctx;
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scc_ir2mcode_init(&mcode_ctx, &ast2ir_ctx.builder.cprog,
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&ast2ir_ctx.builder.ctx, SCC_MCODE_ARCH_AMD64);
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scc_ir2mcode(&mcode_ctx);
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const sccf_t *sccf = sccf_builder_to_sccf(&mcode_ctx.builder);
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scc_pe_builder_t pe_builder;
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sccf2pe(&pe_builder, sccf);
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char fname[1024] = {0};
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scc_snprintf(fname, sizeof(fname), "%s%s%s", __FILE__, "/../../", name);
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scc_pe_dump_to_file(&pe_builder, fname);
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}
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int main() {
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test_example("int main() {\n"
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" int a;\n"
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" int b;\n"
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" a = 1 + 2 * 3;\n"
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" b = 7;\n"
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" a = a - b + 1;\n"
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" return a;\n"
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"}\n",
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true, "02_decl_expr.exe");
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test_example("int main(void) {\n"
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" int a;\n"
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" a = 1;\n"
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" if (a) {\n"
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" a = 1;\n"
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" } else {\n"
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" a = 2;\n"
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" }\n"
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" return a;\n"
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"}\n",
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true, "04_if.exe");
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test_example("int main() {\n"
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" int i = 0;\n"
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" while (i < 10) i = i + 1;\n"
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" return i;\n"
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"}\n",
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true, "07_while.exe");
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test_example("int add(int a, int b) {\n"
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" return a + b;\n"
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"}\n"
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"\n"
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"int main(void) {\n"
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" return add(1, 2);\n"
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"}\n",
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true, "10_call.exe");
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return 0;
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}
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